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13x^2-169=0
a = 13; b = 0; c = -169;
Δ = b2-4ac
Δ = 02-4·13·(-169)
Δ = 8788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8788}=\sqrt{676*13}=\sqrt{676}*\sqrt{13}=26\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26\sqrt{13}}{2*13}=\frac{0-26\sqrt{13}}{26} =-\frac{26\sqrt{13}}{26} =-\sqrt{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26\sqrt{13}}{2*13}=\frac{0+26\sqrt{13}}{26} =\frac{26\sqrt{13}}{26} =\sqrt{13} $
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